(x-5)^2-(2x-7)=8(8-x)

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Solution for (x-5)^2-(2x-7)=8(8-x) equation: 



(x-5)^2-(2x-7)=8(8-x)

We move all terms to the left:

(x-5)^2-(2x-7)-(8(8-x))=0

We add all the numbers together, and all the variables

(x-5)^2-(2x-7)-(8(-1x+8))=0

We get rid of parentheses

(x-5)^2-2x-(8(-1x+8))+7=0



We calculate terms in parentheses: -(8(-1x+8)), so:

8(-1x+8)

We multiply parentheses

-8x+64

Back to the equation:

-(-8x+64)



We add all the numbers together, and all the variables

-2x+(x-5)^2-(-8x+64)+7=0

We get rid of parentheses

-2x+(x-5)^2+8x-64+7=0

We add all the numbers together, and all the variables

6x+(x-5)^2-57=0

We move all terms containing x to the left, all other terms to the right

6x+(x-5)^2=57

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